Re: XPath equivalent to xsl:apply-templates?

Hi Roger,

>  [As I recall Dimitre is working to show how every construct in XSLT can
be represented in XPath. Okay, Dimitre, what's the XPath equivalent of
xsl:apply-templates?]

I don't remember ever making such a statement. ?!?

And in my work it has never been raised as a problem to represent the
generic <xsl:apply-templates> in pure Xpath.

Perhaps, if we have a more understandable and simple example, we could
understand what it exactly is that you need, and why you need it in the
first place?

Once again: while it may be possible in XPath to implement function
dispatch based on arguments' type and context, I don't see why someone
would need to do this. Suppose we could write an XSLT processor in pure
XPath, then the result will still be essentially XSLT with its fundamental
principles and ideas.

Thanks,
Dimitre

On Sun, Jun 12, 2022 at 11:06 AM Roger L Costello costello@xxxxxxxxx <
xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:

> Hi Folks,
>
> I have inserted XPath code into an XML document, e.g.,
>
>    <identifier>$ARPT_row/ICAO</identifier>
>
> I wrote some code that extracts the XPath code and generates an XSLT
> template:
>
>     <xsl:template match="airports/airport/identifier">
>         <xsl:param name="ARPT_row" tunnel="yes"/>
>         <identifier>
>             <xsl:value-of select="$ARPT_row/ICAO"/>
>         </identifier>
>     </xsl:template>
>
> In some cases, I want to generate an XSLT template that has an
> xsl:apply-templates, e.g.,
>
>     <xsl:template match="airports">
>         <xsl:param name="ARPT_row" tunnel="yes"/>
>         <airports>
>             <xsl:for-each select="$ARPT.XML/ARPT/row">
>                 <xsl:apply-templates select="current()/*">
>                     <xsl:with-param name="ARPT_row" tunnel="yes"
> select="."/>
>                 </xsl:apply-templates>
>             </xsl:for-each>
>         </airports>
>     </xsl:template>
>
> What XPath code to put in the XML document <airports> element:
>
>    <airports>???</airports>
>
> The xsl:for-each can be replaced with the XPath "for" statement:
>
>    <airports>for $i in $ARPT.XML/ARPT/row return ???</airports>
>
> Do you have suggestions for an XPath that results in generating
> xsl:apply-templates?
>
> Is there an XPath equivalent to xsl:apply-templates? (Not sure if that
> question makes sense)
>
> [As I recall Dimitre is working to show how every construct in XSLT can be
> represented in XPath. Okay, Dimitre, what's the XPath equivalent of
> xsl:apply-templates?]
>
> /Roger
> 
>
>

-- 
Cheers,
Dimitre Novatchev
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