Re: XQuery/XPath 3.1: Node List to Node Set ("distinct

On Wed, 2021-12-29 at 19:06 +0000, Dimitre Novatchev
dnovatchev@xxxxxxxxx wrote:
> On Wed, Dec 29, 2021 at 10:27 AM Martin Honnen martin.honnen@xxxxxxx <
> xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:
> 
> I am happy to state that the provided solution produces the correct
> result
> on all currently-existing XPath engines :)

Does that include Oracle and DB2? What if the XPath expression is used
inside an "unordered" expression?


Probably it works well enough in practice; if it was part of a library
i was distributing, at the very least i'd want to document that the
order is not guaranteed.

Liam

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