Re: with XPath 1.0, select all following sibling eleme

> I am facing an XPath problem

The answers so far have answered the question asked, but I wonder if that
is the wrong question.

To select the consecutive sequence of foo elements in xpath 1 requires some
kind of double pass over the list and quadratic behaviour in the number of
elements in the list.

However if (as appears the case) the question is in an XSLT context rather
than pure Xpath, you can usually avoid selecting the elements in a single
expression.
this does a single pass over the list stopping at the first non-foo element
so is linear complexity

xpath is just used to select one element at a time, the logic of handling
just foo elements is pushed to a specific XSLT mode that only handles foo
and stops at anything else,

Given

<x>

 <b>
  <foo>1</foo>
  <foo>2</foo>
  <bar>x</bar>
  <foo>3</foo>
 </b>

 <b>
  <foo>4</foo>
  <foo>5</foo>
  <foo>6</foo>
 </b>

 <b>
  <bar>y</bar>
  <foo>7</foo>
  <foo>8</foo>
 </b>

</x>


this stylesheet

<xsl:stylesheet version="1.0" xmlns:xsl="
http://www.w3.org/1999/XSL/Transform">

 <xsl:template match="b">
   <zzz>
   <xsl:apply-templates mode="onlyfoo" select="*[1]"/>
   </zzz>
 </xsl:template>

 <xsl:template mode="onlyfoo" match="*"/>

 <xsl:template mode="onlyfoo" match="foo">
  <xsl:copy-of select="."/>
  <xsl:apply-templates mode="onlyfoo" select="following-sibling::*[1]"/>
 </xsl:template>

</xsl:stylesheet>


produces


 <zzz><foo>1</foo><foo>2</foo></zzz>

 <zzz><foo>4</foo><foo>5</foo><foo>6</foo></zzz>

 <zzz/>