Re: compare two node sets

On 21.01.2020 17:34, Wolfhart Totschnig wolfhart.totschnig@xxxxxxxxxxx
wrote:

Thank you for your solution. I have a question about it, which has to do
with the fact that, in my case, the <author>/<director> elements also
may have a <middle> child element, which I did not mention in my
original post. Now, if I understand correctly, your solution does not
differentiate between

 B B B B B B B  <director>
 B B B B B B B B B B  <first>J.</first>
 B B B B B B B B B B  <middle>R.</first>
 B B B B B B B B B B  <last>Doe</last>
 B B B B B B B  </director>

and

 B B B B B B B  <director>
 B B B B B B B B B B  <first>J. R.</first>
 B B B B B B B B B B  <last>Doe</last>
 B B B B B B B  </director>

Is that right? (I am not saying that this is necessarily a problem. It
may even be seen as a feature rather than a bug. I just want to be sure
that I understand the solution correctly.)

I guess first you would need to adapt the function to select all three
elements e.g.
   string-join($who/(first, middle, last), ' ')
or
  string-join($who/*, ' ')

But you are right that it couldn't distinguish your two inputs although
of course using a different second argument to string-join like '|'
instead of the space would allow that.

On 21.01.20 12:42, Piez, Wendell A. (Fed) wendell.piez@xxxxxxxx wrote:

Hi,

Another solution not yet suggested in this thread is to avoid
deep-equal() and rely on a signature function.

So for example,

<xsl:function name="f:signature" as="xs:string">
B B  <xsl:param name="who" as="node()"/>
B B  <xsl:value-of select="string-join($who/(first, last), ' ')"/>
</xsl:function>

Then your list of author-directors is
//author[f:signature(.)=parent::film/child::director/f:signature(.)]

(Or the other way around.)

Wrap the expression in the filter in not() to retrieve authors who did
not direct, etc.

One advantage of this approach is it's easy to adjust the signature
logic to real-world exigencies.