Re: for-each-group

My general intent is to group on figure elements. All consecutive siblings
that aren't <figure>s (<para> or otherwise) should be in their own group.

Michael's solution works, but I am having trouble getting my head around the
logic. Thank you Martin and Michael for the quick replies.

Rick



-----Original Message-----
From: Martin Honnen martin.honnen@xxxxxx
<xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Wednesday, March 28, 2018 12:01 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re:  for-each-group

On 28.03.2018 17:53, Rick Quatro rick@xxxxxxxxxxxxxx wrote:

> I have a <step> element that looks something like this:
>
> <steps>
>
>    <step>
>
>      <para>Intro stuff</para>
>
>      <para>More intro stuff</para>
>
>      <figure/>
>
>      <figure/>
>
>      <para>Conclusion stuff</para>
>
>      <para>More conclusion stuff</para>
>
>    </step>
>
> </steps>
>
> I want 4 separate groups:
>
> 1) First two <para> elements.
>
> 2) First <figure>
>
> 3) Second <figure>
>
> 4) Last two <para> elements.

Can you explain the rules for that result, do you want to group any adjacent
"para" element into one group but keep each "figure" element in its own
group?

In that case you can use

   <xsl:for-each-group select="*" group-adjacent="boolean(self::para)">
     <xsl:choose>
        <xsl:when test="current-grouping-key()">
          <group>
             <xsl:apply-templates select="current-group()"/>
          </group>
       </xsl:when>
       <xsl:otherwise>
         <xsl:for-each select="current-group()">
            <group>
               <xsl:apply-templates select="."/>
            </group>
         </xsl:for-each>
       </xsl:otherwise>
    </xsl:choose>
   </xsl:for-each-group>