Re: Increasing sequence ?

Isn't it reasonable to assume that a sequence implementation has the number
of items "ready to use"?

Perhaps someone with insight into implementations can answer that?

-W

On 26 March 2015 at 03:42, Dimitre Novatchev dnovatchev@xxxxxxxxx <
xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:

> On Wed, Mar 25, 2015 at 11:51 AM, Wolfgang Laun
> wolfgang.laun@xxxxxxxxx <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
> wrote:
> >> not($seq[2])  or $seq[1] lt $seq[2]  and  increasing(subsequence($seq,
> 2))
> >
> >
> > It would appear that this makes -1,0,2,1 an ascending sequence. I dislike
> > this "empty-is-false trick" - once in a while you get bitten.
> >
> > count($seq) &lt; 2 or ...
>
> Yes, good to remind that we are dealing with items -- not just nodes.
>
> > count($seq) &lt; 2 or ...
>
> No, the idea is to avoid count, as this may add the time for one
> unnecessary pass over the sequence. And the solution can be adjusted
> naturally:
>
>   <xsl:function name="my:increasing" as="xs:boolean">
>     <xsl:param name="pSeq" as="item()*"/>
>
>     <xsl:sequence select=
>       "empty($pSeq[2])
>       or
>        $pSeq[1] lt $pSeq[2]  and  my:increasing(subsequence($pSeq, 2))"/>
>   </xsl:function>
>
>
>
>
> --
> Cheers,
> Dimitre Novatchev
> ---------------------------------------
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