Re: XSL 1.0 - sum values taken from corresponding colu

I think that in XSLT 1 the only solution would be to use sibling recursion:

<xsl:template name="sumcells">
  <xsl:param name="inSum"/>
  <xsl:variable name="sum" select="$inSum + number(.)"/>
  <xsl:choose>
    <xsl:when test="count(following-sibling::cell) = 0">
      <xsl:value=of select="$sum"/>
    </xsl:when>
    <xsl:otherwise>
     <xsl:for-each select="following-sibling:cell[1]">
       <xsl:with-param name="inSum" select="$sum"/>
     </xsl:for-each>
   </xsl:otherwise>
  </xsl:choose>
</xsl:template>

Cheers,

E.

bbbbb
Eliot Kimber, Owner
Contrext, LLC
http://contrext.com




On 2/12/15, 5:42 AM, "Kevin Bird kevinbrianbird@xxxxxxxxx"
<xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:

>Hello,
>
>In <col2>, where cell = num, return the corresponding col1/cell/@value,
>summing the result.
>
><root>
>	<col1>
>		<cell value="1">text</cell>
>		<cell value="12">text</cell>
>		<cell value="24">text</cell>
>		<cell value="100">text</cell>
>		<cell value="9">text</cell>
>		<cell value="6">text</cell>
>	</col1>
>	<col2>
>		<cell>num</cell>
>		<cell>-</cell>
>		<cell>num</cell>
>		<cell>-</cell>
>		<cell>num</cell>
>		<cell>num</cell>
>	</col2>
>	<col3>
>		<cell>-</cell>
>		<cell>num</cell>
>		<cell>num</cell>
>		<cell>num</cell>
>		<cell>num</cell>
>		<cell>-</cell>
>	</col3>
></root>
>
>Sum for <col2> is: 40
>
>Sum for <col3> is: 145
>
>I'd like an XPath solution, but I don't think that is possible.
>
>I tried using keys.
>
><xsl:key name="byValue" match="cell" use="/root/col1/cell[position() =
>count(current()/preceding-sibling::cell)+1]/@value"/>
>
>So each cell has the correct value, but I'm struggling to sum the values.
>Maybe my thinking is wrong.
>
>Any help appreciated.
>
>--
>Kevin