Re: How would I create this derived field in XML from

*_Below in my xsl code am getting a syntax error on the following line_*

<xsl:variable name="CurrDateTimeValue"
select="format-dateTime(current-dateTime(),"[Y0001][M01][D01][H01][m01]")"/>

	Element type "xsl:variable" must be followed by either attribute
specifications, ">" or "/>".

b&
b&

               <xsl:choose>
       <xsl:when test="contains-case-insensitive($InvoicePOLineOwner,
'Law')">
               <xsl:variable name="POOwnerType" select="W'" />
               </xsl:when>
               <xsl:otherwise>
        <xsl:variable name="POOwnerType" select="L" />
               </xsl:otherwise>
   </xsl:choose>

<xsl:variable name="POOwnerType" as="xs:string">
  <xsl:choose>
    <xsl:when test="matches($InvoicePOLineOwner, 'Law', 'i')">
      <xsl:sequence select="'W'"/>
    </xsl:when>
    <xsl:otherwise>
      <xsl:sequence select="'L'"/>
    </xsl:otherwise>
  </xsl:choose>
</xsl:variable>

<xsl:variable name="POOwnerType" as="xs:string"
  select="if (matches($InvoicePOLineOwner, 'Law', 'i'))
          then 'W' else 'L'"/>