Re: Copying Namespace Nodes

I have an element I want to copy and in the source it looks like this:

<a:elem
  xmlns:a="example.com/ns/a"
  xsi:type="nsc:foo"
  xmlns:nsc="example.com/ns/sensitive"
  xmlns:b="example.com/ns/b"
  xmlns:c="example.com/ns/c"
  ...
  xmlns:z="example.com/ns/z">info</a:elem>

What I want to achieve at the same time:

1) Keep the namespace declaration for the namespace sensitive content of
the xsi:type attribute (with prefix nsc).

2) Get rid of all namespace declarations that are not needed here (prefix
b, c, ..., z) and that clutter up my result document.

If I use copy-of with copy-namespaces set to 'no' the declaration for
namespace sensitive content will be lost. If I say 'yes' everything stays
the same. So is there a short way I have not seen yet or is the solution
some verbose template? :)

<xsl:template match="*">
  <xsl:copy copy-namespaces="no">
    <xsl:for-each select="@xsi:type">
      <xsl:copy-of
          select="../namespace::*[name(.)=substring-before(current(),':')]"/>
      <xsl:copy/>
    </xsl:for-each>
  </xsl:copy>
</xsl:template>

</xsl:stylesheet>
T:\ftemp>

Thanks for help,
Heiko

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