Re: xpath-default-namespace with a variable

On 19 September 2011 14:06, Murray McDonald <m.mcdonald@xxxxxxxxx> wrote:
> I am using XSLT 2 via AltovaXML.
>
> I have a need to look up "key" terms in an external glossary document.  The
> external document has a default namespace at the root level.  The code
works
> fine like this:
>
> <xsl:param name="GLOSSARY" select="'./working_files/glossary.xml'"/>
>
> <xsl:key name="definitions" match="glossentry" use="term/@key"
> xpath-default-namespace="http://www.abcdef.com/hij"/>
>
> <xsl:variable name="glossaryDocument" select="document($GLOSSARY)"/>
>
> ...
>
> <xsl:variable name="definition">
>        <xsl:for-each select="$glossaryDocument">
>                <xsl:value-of select="key('definitions',
> $normalizedText)/definition" xpath-default-namespace="
> http://www.abcdef.com/hij"/>
>        </xsl:for-each>
> </xsl:variable>
>
> After testing I decided to replace the "hardcoded" namespace with a
"global"
> variable.  I was surprised to find that this did not work.
>
> <xsl:variable name="glossNS" select="'http://www.abcdef.com/hij'"
> as="xs:anyURL"/>
>
> <xsl:key name="definitions" match="glossentry" use="term/@key"
> xpath-default-namespace="{$glossNS}"/>
>
> ...
>
>                <xsl:value-of select="key('definitions',
> $normalizedText)/definition" xpath-default-namespace="{$glossNS}"/>
>
> I've check the spec and I can't find anything to make me believe this
> shouldn't work but it's entirely possible I may have missed some subtlety.

You can't declare namespaces using AVTs.... I would just declare the
namespace with a prefix once on your root element and then use that in
the key definition:

<xsl:stylesheet ... xmlns:foo="http://www.abcdef.com/hij">

<xsl:key name="definitions" match="foo:glossentry" use="term/@key"/>



--
Andrew Welch
http://andrewjwelch.com