Re: passing filtered tree to template

<xsl:template match="items">
    <xsl:apply-templates select="item" />
</xsl:template>

<!-- called ONLY when property X is true -->
<xsl:template match="item[property='x']">
    <myItem>
        <xsl:value-of select="index"/>
    </myItem>
</xsl:template>

<!-- called for all other situations (may leave empty if you don't want to process them) -->
<xsl:template match="item">
    <otherItem>
        <xsl:value-of select="index"/>
    </otherItem>
</xsl:template>

Hi
I have the following problem: Given an xml like the following:

<test>
     <items>
         <item>
             <index>1</index>
             <property>x</property>
         </item>
         <item>
             <index>2</index>
             <property>y</property>
         </item>
         <item>
             <index>3</index>
             <property>x</property>
         </item>
     </items>
</test>

and a stylesheet like:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
     <xsl:template match="test">
         <myTest>
         <xsl:variable name="xItems">
             <xsl:copy-of select="items"/>
         </xsl:variable>
             <xsl:apply-templates
select="items[item/property='y']"/><!-- wrong try! -->
         </myTest>
     </xsl:template>

     <xsl:template match="items">
         <xsl:for-each select="item">
             <myItem>
                 <xsl:value-of select="index"/>
             </myItem>
         </xsl:for-each>
     </xsl:template>
</xsl:stylesheet>

I would like to pass only the items with property='x' to the items
matching template. The first try as written above of course doesn't
work, if there is an x item then the whole tree is passed, if there is
none, nothing is passed. I do further processing in the items
template, so I don't want to change it to match="item" or to apply the
filter in the items template.

Any help is much appreciated!

thanks, kind regards

Stefan