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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] spreadsheet xml and group-starting-with
 I have a MS spreadsheet xml that I will be transforming into an html table.
I need to use group-starting-with to group multiple rows into one
based on empty cells in the first column.
ex. If I have
Col A, Col b, Col c
1a, 1b, 1c
, 2b, 2c
, ,3c
4a,4b,4c
, ,5c
---
I will eventually create a html table with two rows and three columns.
For now I am trying to just get grouping to work, but I got stuck.
Just when I thought I had for-each-group figured out I get stumped again.
Can you get me going in the right direction?
Sample MS Xml
---------------------------------------------------------------------
<Workbook xmlns="urn:schemas-microsoft-com:office:spreadsheet"
xmlns:ss="urn:schemas-microsoft-com:office:spreadsheet">
<Worksheet>
<Table>
<Row>
<Cell><Data ss:Type="String">1a</Data></Cell>
<Cell><Data ss:Type="String">1b</Data></Cell>
<Cell><Data ss:Type="String">1c</Data></Cell>
</Row>
<Row>
<Cell ss:Index="2"><Data ss:Type="String">2b</Data></Cell>
<Cell><Data ss:Type="String">2c</Data></Cell>
</Row>
<Row>
<Cell ss:Index="3"><Data ss:Type="String">3c</Data></Cell>
</Row>
<Row>
<Cell><Data ss:Type="String">4a</Data></Cell>
<Cell><Data ss:Type="String">4b</Data></Cell>
<Cell><Data ss:Type="String">4c</Data></Cell>
</Row>
<Row>
<Cell ss:Index="3"><Data ss:Type="String">5c</Data></Cell>
</Row>
</Table>
</Worksheet>
</Workbook>
---------------------------------------------------------------------
End Sample MS Xml
Notice, they optimize cells by using ss:Index="" when they skip cells.
And leave that attribute out when they don't. I figured this would be
a good thing to group on.
My xslt
---------------------------------------------------------------------
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:ss="urn:schemas-microsoft-com:office:spreadsheet">
<xsl:output encoding="iso-8859-1" method="xml" indent="yes"/>
<xsl:template match="ss:Workbook">
<body>
<xsl:apply-templates select="ss:Worksheet[1]/ss:Table"/>
</body>
</xsl:template>
<xsl:template match="ss:Table">
<xsl:for-each select="ss:Row">
<xsl:if test="ss:Cell[1][not(@ss:Index)]"><data>grouping
row</data></xsl:if>
</xsl:for-each>
<data>show them grouped now</data>
<xsl:for-each-group select="ss:Row"
group-starting-with="ss:Cell[1][not(@ss:Index)]">
<group>
<xsl:copy-of select="current-group()"/>
</group>
</xsl:for-each-group>
</xsl:template>
</xsl:stylesheet>
---------------------------------------------------------------------
End My xslt
In my output, I correctly get two "<data>grouping row</data>" nodes.
But I only get one <group>{stuff}</group>
I would have expected two.
For this example, I want output that looks something like the following.
It doesn't have to be exact, but if I can get two groups with the
implied cell data, then I can probably go from there, I hope.
---------------------------------------------
<group>
<Row>
<Cell><Data ss:Type="String">1a</Data></Cell>
<Cell><Data ss:Type="String">1b</Data></Cell>
<Cell><Data ss:Type="String">1c</Data></Cell>
</Row>
<Row>
<Cell ss:Index="2"><Data ss:Type="String">2b</Data></Cell>
<Cell><Data ss:Type="String">2c</Data></Cell>
</Row>
<Row>
<Cell ss:Index="3"><Data ss:Type="String">3c</Data></Cell>
</Row>
</group>
<group>
<Row>
<Cell><Data ss:Type="String">4a</Data></Cell>
<Cell><Data ss:Type="String">4b</Data></Cell>
<Cell><Data ss:Type="String">4c</Data></Cell>
</Row>
<Row>
<Cell ss:Index="3"><Data ss:Type="String">5c</Data></Cell>
</Row>
</group>
------------------------------------------
Thanks
Fred
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