Re: Getting previous node in nodeset

And, of course, a solution which doesn't use subsequence() :

  for $i in (1 to count($nodelist))
    return $nodelist[$i][$nodelist[$i +1] is $mynode]


--
Cheers,
Dimitre Novatchev
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Truly great madness cannot be achieved without significant intelligence.
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To invent, you need a good imagination and a pile of junk
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Never fight an inanimate object
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You've achieved success in your field when you don't know whether what
you're doing is work or play
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Facts do not cease to exist because they are ignored.




On Fri, Apr 22, 2011 at 3:18 AM, Oliver Hallam <oliver@xxxxxxxxxxx> wrote:
> A slightly neater formulation of this is
>
> $nodelist[subsequence($nodelist,position() + 1,1) is $mynode]
>
> If you know your nodelist is in document order, then the following would
> also work:
>
> $nodelist[. << $mynode][last()]
>
>
>
> Oliver Hallam
>
>
> On 22/04/2011 10:21, Michael Kay wrote:
>>
>> On 22/04/2011 08:24, David Carlisle wrote:
>>>
>>> On 22/04/2011 02:28, Steve Fogel wrote:
>>>>
>>>> Hi, all...
>>>>
>>>> Would appreciate a suggestion:
>>>>
>>>> If:
>>>>
>>>> - I have a node set in the variable $nodelist
>>>> - and I have a single node in the variable $mynode
>>>> - and the node in $mynode is a member of $nodelist
>>>>
>>>> then in XSLT 2.0, how do I set a variable to contain the node that is
>>>> previous to $mynode in $nodelist?
>>>>
>>>> For simplicity and a quick answer, you can assume that all nodes in
>>>> $nodelist are siblings, but in reality, $nodelist contains<topicref>s
from a
>>>> DITA map, so the previous node could be a sibling, a parent, or the child
of
>>>> the previous sibling.
>>>>
>>>> Many thanks
>>>>
>>>>
>>>
>>
>> If I had this problem, I think I would want to take a step back: where do
>> these two variables come from? Is there any possibility that instead of
>> setting the variable $mynode to be one of the nodes in $nodelist, one
could
>> set a variable $myNodePosition to be the integer position of $mynode in
>> $nodelist?
>>
>> However, for the problem as stated, another option is
>>
>> $nodelist[(1 to count($nodelist))[subsequence($nodelist, ., 1) is $mynode]
>> - 1]
>>
>> In 3.0 this is a classic case for some useful higher-order functions.
>>
>> Michael Kay
>> Saxonica