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Re: Full output all nodes depending on a conditional

Subject: Re: Full output all nodes depending on a conditional
From: Martin Honnen <Martin.Honnen@xxxxxx>
Date: Sun, 14 Nov 2010 18:21:06 +0100
Re:  Full output all nodes depending on a conditional
Jimenez, Luis wrote:

   <xsl:template match="pd">
     <xsl:copy>
       <xsl:variable name="id" select="translate(detfac/pie/linea3,',','')"/>
      <xsl:if test="$id&gt; '500'">

Note that '>' and '<' with XSLT 1.0 work only on numbers so your '500' is converted the the number 500 anyway, meaning you could directly use
<xsl:if test="$id > 500">


<xsl:apply-templates select="@* | picking"/>

I think you simply want to change the above to
<xsl:apply-templates select="@* | node()"/>
to ensure not only the "picking" child elements but others like the "detfac" are processed as well.


--

	Martin Honnen
	http://msmvps.com/blogs/martin_honnen/

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