[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Question about grouping
Hi,
At 02:51 AM 9/24/2010, Mike wrote: Both methods Also, the count(A)=count(A|B) method is a particular case of a more general set of methods for node set operations that aren't directly supported in XPath 1.0. For example, $A[count(.|$B)=count($B)] is a way of performing node set intersection, where both $A and $B can be sets of more than one. And $A(count(.|$B)!=count($B)) is an 'except'. Fortunately, all these are unnecessary in XPath 2.0 The generate-id(.) method may be a little easier to get your head around, at least once you've mastered what the generate-id() does. (But then you learn the other idiom too.) Cheers, Wendell ====================================================================== Wendell Piez mailto:wapiez@xxxxxxxxxxxxxxxx Mulberry Technologies, Inc. http://www.mulberrytech.com 17 West Jefferson Street Direct Phone: 301/315-9635 Suite 207 Phone: 301/315-9631 Rockville, MD 20850 Fax: 301/315-8285 ---------------------------------------------------------------------- Mulberry Technologies: A Consultancy Specializing in SGML and XML ======================================================================
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