RE: Noobie: normalize <b><a>...</a></b> to <a><b>...<

Two templates: an identity template that copies everything by default

<xsl:template match="*">
  <xsl:copy>
    <xsl:copy-of select="@*"/>
    <xsl:apply-templates/>
  </
</

and a template for the nodes you want to change:

<xsl:template match="b[a][count(child::node()=1]">
  <a>
    <b>
      <xsl:apply-templates select="a/child::node()"/>
    </b>
  </a>
</xsl:template>

Regards,

Michael Kay
http://www.saxonica.com/
http://twitter.com/michaelhkay 
 

> -----Original Message-----
> From: Kenneth Reid Beesley [mailto:krbeesley@xxxxxxxxx] 
> Sent: 18 February 2010 17:55
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject:  Noobie: normalize <b><a>...</a></b> to 
> <a><b>...</b></a>
> 
> 
> I'm converting a non-XML data-dump into XML, and the document 
> contains examples of both
> 
> <a><b>...</b></a>
> 
> and
> 
> <b><a>...</a></b>
> 
> which (in this document) are equivalent.  I'd like to use 
> XSLT to convert all examples of the latter to the former, 
> with the following
> caveats:
> 
> 1.  <b> can contain mixed text, in which case nothing should 
> be changed.
> 2.  <b><a>...</a></b> should be changed to <a><b>...</b></a> 
> only if the <a>...</a> element is the unique child node of <b>...</b>
> 
> How can I do this?
> 
> Thanks,
> 
> Ken
> 
> ******************************
> Kenneth R. Beesley, D.Phil.
> P.O. Box 540475
> North Salt Lake, UT
> 84054  USA