RE: XML attribute value to pattern match of the replac

Thanks for the help. 

>You need to concat the attribute values e.g.
>   select="replace(., concat('(', @party1, '.*?', @party2, ')'), 
>'<cite>$1</cite>')"

In case the xml content appear parenthesis () does not process the replace
function can u suggest any other way.

Also I have tried below way, but does not working.

select="(concat('(', string(@party1), '.*?', string(@party2), ')'),
'<cite>$1</cite>')"/>


Also I have tried the analyze-string method but it was working fine but
above issue was repeated. 

<xsl:element name="caseref">
<xsl:analyze-string select="." regex="({@party1}.*?{@party2})">
     <xsl:matching-substring>
        <xsl:element name="casetitle">
          <xsl:value-of select="regex-group(1)"/>
        </xsl:element>
     </xsl:matching-substring>
     <xsl:non-matching-substring>
        <xsl:value-of select="."/>
     </xsl:non-matching-substring>
   </xsl:analyze-string>
</xsl:element>
</xsl:template>

Sample input:

<caseref party1="President of South Africa" party2="Modderklip Boerdery
(Pty) Ltd">President of South Africa v Modderklip Boerdery (Pty)
Ltd</caseref>

But the replacement looks as if you want to insert a 'cite' element so 
using analyze-string instead of replace might be what you really want. 
So instead of the value-of use e.g.

   <xsl:analyze-string select="." regex="({@party1}.*?{@party2})">
     <xsl:matching-substring>
        <cite>
          <xsl:value-of select="regex-group(1)"/>
        </cite>
     </xsl:matching-substring>
     <xsl:non-matching-substring>
        <xsl:value-of select="."/>
     </xsl:non-matching-substring>
   </xsl:analyze-string>

The above is untested.


-- 

	Martin Honnen
	http://msmvps.com/blogs/martin_honnen/



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