Re: sequential numbering in xslt

Hi James

Thanks for your help.

I am using saxon 9.1. And when I tried giving a full path to the
folder holding XML files as shown below, saxon errors out.
	<xsl:with-param name="documents" select="collection('C/input/*.xml')"/>

It says it cannot find the file or directory.

Can I not use the complete file path in the colleciton() function with SAxon?


On Mon, Jan 4, 2010 at 11:52 AM, James A. Robinson
<jim.robinson@xxxxxxxxxxxx> wrote:
>
>> another XML format using XSLT. The output XML file has a schema and
>> has a required 'seq' attribute in the root element that needs to be
>> incremented for each input XML file.
>> ...
>> for every input file, in the transformation, I want to increment
>> attribute 'seq' in the output file by 1 when I transform the input
>> files using xslt.
>> I  have tried <xsl:number> and tried writing a function. But the
>> problem is that since variables in xslt are constants, there is no way
>> to increment a number, store it in a temp variable and increment it
>> for the next time in xslt 2.0 unlike procedural languages like C or
>> C++.
>>
>> Is there any other way of achieving this in XSLT 2.0?
>
> Using position() is one option, keeping track of the number of
> documents you are processing yourself, using a recursive template,
> is another:
>
> <?xml version="1.0" encoding="UTF-8"?>
> <xsl:stylesheet version="2.0"
>  xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
>
>  xmlns:xs="http://www.w3.org/2001/XMLSchema"
>
>  exclude-result-prefixes="xs">
>
>  <!-- URI approporiate for fn:collection, e.g., in
>       saxon:
>
>       <collection stable="true">
>         <doc href="file1.xml" />
>         <doc href="file2.xml" />
>         <doc href="file3.xml" />
>       </collection>
>  -->
>  <xsl:param name="collection-href" required="yes" />
>
>  <!-- Previous sequence number, if we need to start at
>       some point other than 1. -->
>  <xsl:param name="previous-number" select="0" />
>
>
>  <xsl:template match="/">
>    <xsl:call-template name="example">
>      <xsl:with-param name="documents" select="collection($collection-href)"
/>
>      <xsl:with-param name="previous-number" select="$previous-number" />
>    </xsl:call-template>
>  </xsl:template>
>
>  <xsl:template name="example">
>    <xsl:param name="documents" />
>    <xsl:param name="previous-number" required="yes" />
>
>    <xsl:if test="$documents[1]">
>      <xsl:variable name="current-number" as="xs:integer"
select="xs:integer($previous-number+1)" />
>
>      <!-- Here we could use xsl:result-document and xsl:apply-templates
>           to kick off processing of our input document. -->
>      <example seq="{$current-number}" />
>
>      <!-- Now we recursively process the next document in our list -->
>      <xsl:call-template name="example">
>        <xsl:with-param name="documents" select="remove($documents, 1)" />
>        <xsl:with-param name="previous-number" select="$current-number" />
>      </xsl:call-template>
>    </xsl:if>
>
>    <!-- Here, if not($documents), we could write out our
>         last number to some file that we use to track our
>         sequence number across time. -->
>  </xsl:template>
>
> </xsl:stylesheet>
>
> Running this w/ the example collection document and no override
> of $previous-number would produce
>
> <example seq="1"/>
> <example seq="2"/>
> <example seq="3"/>
>
> whereas setting $previous-number to 3 would produce
>
> <example seq="4"/>
> <example seq="5"/>
> <example seq="6"/>
>
>
> Jim
>
> - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
> James A. Robinson                       jim.robinson@xxxxxxxxxxxx
> Stanford University HighWire Press      http://highwire.stanford.edu/
> +1 650 7237294 (Work)                   +1 650 7259335 (Fax)