Re: sort a node across a dynamic group of files

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Subject: Re: sort a node across a dynamic group of files
From: "G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx>
Date: Sun, 22 Nov 2009 15:06:20 -0500

BTW, I prematurely sent my example without explaining why I put the items in a variable.

At 2009-11-22 14:57 -0500, I wrote:

      <!--$docs is ready with all documents-->
      <!--sort by name-->
      <xsl:variable name="names" select="$docs/doc/name"/>
      <xsl:for-each select="$names">
        <xsl:sort select="."/>
        <xsl:text>
</xsl:text>
        <xsl:value-of select="."/>
      </xsl:for-each>

Of course you don't need the variable above, you can just work with:

     <xsl:for-each select="$docs/doc/name">
        <xsl:sort select="."/>
        ...

But I had it in my mind you were asking about *grouping* across files and not just *sorting* across files. If you needed to group by common names, then putting them in a variable would allow you to find the common names and group under them as common headings.

Here are posts from 2004 and 2006 that show what you can do for grouping once you have the variable loaded from multiple files:

 http://www.biglist.com/lists/xsl-list/archives/200410/msg00412.html
 http://www.stylusstudio.com/xsllist/200603/post70000.html

But in the end I realized you weren't asking for grouping and I failed to undo the preparations I had made.

I hope this helps.

. . . . . . . . . Ken

--
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Current Thread

sort a node across a dynamic group of files
- J . Argyl Plath - 22 Nov 2009 19:28:37 -0000
  - Martin Honnen - 22 Nov 2009 19:52:15 -0000
    - J. Argyl Plath - 22 Nov 2009 19:57:56 -0000
  - G. Ken Holman - 22 Nov 2009 19:58:16 -0000
    - G. Ken Holman - 22 Nov 2009 20:06:45 -0000 <=
      - J. Argyl Plath - 22 Nov 2009 20:29:05 -0000
      - ac - 23 Nov 2009 04:33:13 -0000
      - Syd Bauman - 23 Nov 2009 04:41:46 -0000
      - ac - 23 Nov 2009 06:16:42 -0000

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