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<aaa><xsl:value-of select=".../aaa"/></aaa>
<bbb><xsl:value-of select=".../bbb"/></bbb>
<ccc><xsl:value-of select=".../ccc"/></ccc>

Or something like it (judging from the "...")

If it's simple enough, you can simply do

<xsl:copy-of select="aaa|bbb|ccc"/>

But I don't think you've told us the whole truth, so it might have to be
something like

<xsl:if test="...aaa">
  <aaa>
    <xsl:value-of ...
  </aaa>
</xsl:if>

etc.

Regards,

Michael Kay
http://www.saxonica.com/
http://twitter.com/michaelhkay 


> -----Original Message-----
> From: Ben Stover [mailto:bxstover@xxxxxxxxxxx] 
> Sent: 07 October 2009 13:10
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject:  How to copy only the really existing <choice> 
> branch/element? "value-of-if-exist"
> 
> Assume I have a XML source based on the following 
> (simplified) XSD schema:
> 
> <xsd:element name="top" type="mytype"/>
> 
> <xsd:complexType name="mytype">
>   <xsd:choice>
>     <xsd:element name="aaa" type=".....">
>     <xsd:element name="bbb" type=".....">
>     <xsd:element name="ccc" type=".....">
>   </xsd:choice>
> </xsd:complexType>
> 
> That mean either element aaa or element bbb or element ccc is 
> filled/exists.
> 
> Now I want to copy only this sub-element to a target which 
> currently exists.
> 
> If I simply write:
> 
> <xsl:value-of select=".../aaa"/>
> <xsl:value-of select=".../bbb"/>
> <xsl:value-of select=".../ccc"/>
> 
> then ALL three elements were copied. The 2 branches which do 
> not exist were created as empty elements so that the target 
> XML doc looks like e.g.
> 
> <top>
> <aaa></aaa>
> <bbb>myvalue</bbb>
> <ccc></ccc>
> </top>
> 
> which is an invalid XML because of its XSD schema file definition.
> 
> The question is now: How can I let XSL copy only this 
> branch/element which really exists?
> I need a function like
> 
> <xsl:value-of-only-the-existing-choice-branch select=..../top"/>
> 
> or
> 
> <xsl:value-of-if-exists select=".../aaa"/> 
> <xsl:value-of-if-exists select=".../bbb"/> 
> <xsl:value-of-if-exists select=".../ccc"/>
> 
> How can I do this in detail?
> 
> Thank you
> Ben

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