[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Getting sibling nodes from unique values
Sweet! That will teach me to stop overcomplicating things! Thanks a TON!! This is the xsl that i ended up with... <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0"> <xsl:output method="xml"/> <xsl:template match="/"> <xsl:for-each-group select="Root/row" group-by="company"> <xsl:result-document href="{current-grouping-key()}.xml"> <Root> <xsl:copy-of select="current-group()"/> </Root> </xsl:result-document> </xsl:for-each-group> </xsl:template> </xsl:stylesheet> On Tue, Aug 4, 2009 at 10:27 AM, Martin Honnen<Martin.Honnen@xxxxxx> wrote: > Mike Ferrari wrote: > >> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" >> version="2.0"> >> <xsl:output method="text"/> >> <xsl:template match="/"> >> <xsl:for-each select="distinct-values(//company)"> > > Use > <xsl:for-each-group select="Root/row" group-by="company"> > <xsl:result-document href="{current-grouping-key()}.xml"> > <Root> > <xsl:copy-of select="current-group()"/> > </Root> > </xsl:result-document> > </xsl:for-each-group> > > > > > -- > > Martin Honnen > http://msmvps.com/blogs/martin_honnen/ > > -- /dev/mike0 http://www.mikeferrari.com
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