[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: Help on XSL to tranform simple flat xml sequential
In XSLT 2.0 you can do <xsl:for-each-group select="*" group-starting-with="para[@role='title']"> <paragraph> <xsl:apply-templates select="current-group()"/> </paragraph> </xsl:for-each-group> In 1.0 it's rather harder - google for "XSLT positional grouping". Regards, Michael Kay http://www.saxonica.com/ http://twitter.com/michaelhkay > -----Original Message----- > From: Christian Oshiro [mailto:chris_oshiro@xxxxxxxxx] > Sent: 30 August 2009 17:08 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: Help on XSL to tranform simple flat xml sequentially > > This seems like a pretty simple thing to do, but I usually > rely on nested xml. How can I tranform xml that looks like this: > > <para role=title>main title1</para> > <para role=subtitle>subtitle1</para> > <para>This is the body of the paragraph. 1</para> <list>some > stuff 1</list> <para role=title>main title2</para> <para > role=subtitle>subtitle2</para> <para>This is the body of the > paragraph. 2</para> <list>some stuff 2</list> <para > role=title>main title3</para> <para > role=subtitle>subtitle3</para> <para>This is the body of the > paragraph. 3</para> <list>some stuff 3</list> > > I'd like to transform this using xlst to something like this: > > <paragraph> > <title>main title1</title> > > <subtitle>subtitle1</subtitle> > > <body>This is the body of the paragraph. 1</body> > > <list>some stuff 1</list> > </paragraph> > <paragraph> > <title>main title2</title> > <subtitle>subtitle2</subtitle> > <body>This is the body of the paragraph. 2</body> > <list>some stuff 2</list> > </paragraph> > <paragraph> > <title>main title3</title> > <subtitle>subtitle3</subtitle> > <body>This is the body of the paragraph. 3</body> > <list>some stuff 3</list> > </paragraph> > > So i need to go node by node and test when role=title shows > up. Thanks for the insight.
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