[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Re: Determining whether no single instance of a s
On Thu, Jun 4, 2009 at 2:27 PM, Mark Peters <markpeters.work@xxxxxxxxx> wrote: > Sorry, my XSL examples weren't quite right. I'm trying to determine > whether no instance of <c/> exists for each <b/> set. > > So, in my XSL document, assume I'm processing each <a/> node. > > 1, > <xsl:when test="not(b/c)"> > > 2. > <xsl:when test="count(not(b/c)) >= 1"> > > Thanks, > Mark > > > On Thu, Jun 4, 2009 at 2:20 PM, Mark Peters <markpeters.work@xxxxxxxxx> wrote: >> Hi Everyone, >> >> I have the following XML document: >> >> <a> >> <b/> >> <b/> >> <b/> >> </a> >> <a> >> <b/> >> <b/> >> <b> >> <c/> >> </b> >> >> </a> >> <a> >> <b/> >> <b/> >> <b/> >> </a> >> >> For each <b/> set, I want to apply a transformation only if no single >> instance of <c/> exists. I know how to check whether a node does >> exist, but not how to check whether no single instance of the node >> exists. >> >> I've tried the following conditional statements without success: >> >> 1, >> <xsl:when test="not(a/b/c)"> >> >> 2. >> <xsl:when test="count(not(a/b/c)) >= 1"> >> >> >> What conditional statement should I use? >> >> Thanks in advance for any help. >> Are you looking for something along the line of <xsl:when test="not(count(b/c) >= 1)"> ?? -- - michael dykman - mdykman@xxxxxxxxx - All models are wrong. Some models are useful.
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