Re: flattening an xml hierarchy

On 08/01/2009, Evan Lenz <evan@xxxxxxxxxxxx> wrote:
> You probably don't want to process attributes of the unwanted elements.
> With your code below, an attribute on <Dontwant1> would cause a run-time
> error.
>
> Evan
>
> Vasu Chakkera wrote:
>> USe identity transformation.
>>
>> <xsl:stylesheet version="1.0"
>> xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
>> 	<xsl:template match="node()|@*">
>> 		<xsl:copy>
>> 			<xsl:apply-templates select="node()|@*"/>
>> 		</xsl:copy>
>> 	</xsl:template>
>> 	<xsl:template match = "Dontwant1">
>> 		<xsl:apply-templates select="node()|@*"/>
>> 	</xsl:template>
>> 	<xsl:template match = "dontwant2"/>
>> </xsl:stylesheet>
>>
>> This will do your job. Although.. You have 2 definitions of what you
>> want to Remove.
>>
>> 1. Node and its children
>> 2. Node .
>>
>> I am not sure what you meant by "remove" But anyway, in either case,
>> if you want to remove node and all its children, you just define an
>> empty template
>> if you want to ignore the node alone, then you define the template for
>> that node and not bothor about copying the current node, and copy all
>> its children.
>>
>> HTH
>>
>> 2009/1/8 Tim <timlhunt@xxxxxxxxxxxxxx>:
>>
>>> Hi,
>>> I'd like to remove some elements from an xml hierachy using xslt:
>>>
>>> Original xml example:
>>> <Dontwant1>
>>>   <dontwant2>foo</dontwant2>
>>>   <x3>
>>>       <x4>stuff</x4>
>>>       <y5>more stuff</y5>
>>>   </x3>
>>> </Dontwant1>
>>>
>>> Like to have transform output:
>>> <x3>
>>>  <x4>stuff</x4>
>>>   <y5>more stuff</y5>
>>> </x3>
>>>
>>> Thanks for your insghts.
>>>
>>> Tim
>
>


-- 
Vasu Chakkera
Numerical Algorithms Group Ltd.
Oxford
www.vasucv.com