[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: How the other half live
> for $d in distinct-values($seq) return $d[count($seq[. eq $d]) ge $i] > > equivalent? I think it is, and probably a lot more > efficient, although it is longer. > They are both O(n^2). What about: <xsl:for-each-group select="$seq" group-by="."> <xsl:sequence select="current-group()[$i]"/. </xsl:for-each-group> which also scores quite well on brevity, I think - in syntax tree form, it has 6 nodes which is the same as Dimitre's expression; and I think it rates higher on both efficiency and clarity. Michael Kay http://www.saxonica.com/
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