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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Processing on both a document list and referenced doc
 Hi,
I have a set of XML documents and a document list that describes the
directory structure. What I'd like to do is produce output that
displays each folder name in the document list, followed by data
merged from the files listed under each folder.
Sample input file:
file1:
<?xml version="1.0" encoding="utf-8"?>
<!DOCTYPE topic PUBLIC "-//OASIS//DTD DITA Composite//EN" "ditabase.dtd">
<topic id = "topicA">
<title>TitleA</title>
<topic id = "topicB">
<title>TitleB</title>
</topic>
<topic id = "topicC">
<title>TitleC</title>
</topic>
</topic>
Directory list:
<?xml version="1.0" encoding="utf-8"?>
<!DOCTYPE hdlg:filesystem SYSTEM "http://www.hdlg.info/XML/filesystem.dtd">
<hdlg:filesystem xmlns:hdlg="http://www.hdlg.info/XML/filesystem">
<hdlg:folder name="folder1" url="file:/C:/folder1/"/>
<hdlg:folder name="folder2" url="file:/C:/folder2/">
<hdlg:file name="file1.xml" size="14155" type="unknown"
url="file:/C:/folder2/file1.xml"/>
<hdlg:file name="file2.xml" size="132255" type="unknown"
url="file:/C:/folder2/file2.xml"/>
</hdlg:folder>
<hdlg:folder name="folder3" url="file:/C:/folder3/">
<hdlg:file name="file1.xml" size="2455" type="unknown"
url="file:/C:/folder3/file3.xml"/>
<hdlg:file name="file2.xml" size="4355" type="unknown"
url="file:/C:/folder3/file4.xml"/>
</hdlg:folder>
</hdlg:filesystem>
Desired output:
<html>
<body>
<ul>
<li xmlns:hdlg="http://www.hdlg.info/XML/filesystem">file:/C:/folder1/>
<li xmlns:hdlg="http://www.hdlg.info/XML/filesystem">file:/C:/folder2>
<ul>
<li>topicA
<ul>
<li>topicB</li>
<li>topicC</li>
</ul>
</li>
</ul>
<ul>
..
</ul>
<li xmlns:hdlg="http://www.hdlg.info/XML/filesystem">file:/C:/folder3>
..
</ul>
</body>
</html>
My current XSL transformation displays each folder name in a bulleted
list, as desired. But the output includes the entire set of
topic/title values beneath each folder name.
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="html" indent="yes"/>
<xsl:template match="/">
<xsl:variable name="files"
select="document('file:///c:/sabadoc/output/files2.xml')"/>
<html>
<body>
<ul>
<xsl:for-each select="$files//hdlg:folder/@url"
xmlns:hdlg="http://www.hdlg.info/XML/filesystem">
<li>
<xsl:value-of select="."/>
<xsl:for-each select="document($files//hdlg:file/@url)"
xmlns:hdlg="http://www.hdlg.info/XML/filesystem">
<ul>
<xsl:for-each select="topic">
<li>
<xsl:value-of select="title"/>
<ul>
<xsl:for-each select="topic">
<li>
<xsl:value-of select="title"/>
<ul>
<xsl:for-each select="topic">
<li>
<xsl:value-of select="title"/>
</li>
</xsl:for-each>
</ul>
</li>
</xsl:for-each>
</ul>
</li>
</xsl:for-each>
</ul>
</xsl:for-each>
</li>
</xsl:for-each>
</ul>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
Is it possible to produce output based on the contents of both the
directory list and the documents referenced by the directory list?
Thanks,
Mark
--
Mark Peters
Senior Technical Writer
Saba Software
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