[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: first n nodes from a current-group
Thank you very much Michael. It's working. Regards, Manish -----Original Message----- From: Michael Kay [mailto:mike@xxxxxxxxxxxx] Sent: Thursday, February 07, 2008 7:06 PM To: Manish_Jaiswal; xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: RE: first n nodes from a current-group > > But I wanted only the first two name elements having highest counts. > that is output like: > Try <School> <xsl:for-each-group select=" School/student group-by="name/tokenize(., ';\s*')"> <xsl:sort data-type="number" select="count(current-group())" order="descending" /> <xsl:sort select="current-grouping-key()"/> <xsl:if test="position() <= 2"> <name count="{count(current-group())}"> <xsl:value-of select="current-grouping-key()"/> </name> </xsl:if> </xsl:for-each-group> </School> Michael Kay http://www.saxonica.com/ DISCLAIMER: This email (including any attachments) is intended for the sole use of the intended recipient/s and may contain material that is CONFIDENTIAL AND PRIVATE COMPANY INFORMATION. Any review or reliance by others or copying or distribution or forwarding of any or all of the contents in this message is STRICTLY PROHIBITED. If you are not the intended recipient, please contact the sender by email and delete all copies; your cooperation in this regard is appreciated.
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