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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: xpath query
 In XSLT 2.0, when you do <xsl:value-of select="EXPR"/> and EXPR selects a sequence of nodes, the output consists of the string-values of those nodes, separated by a single space. If you want to copy the nodes to the output rather than extracting their string values, try <xsl:copy-of>. Michael Kay http://www.saxonica.com/ > -----Original Message----- > From: Sean Tiley [mailto:sean.tiley@xxxxxxxxx] > Sent: 18 January 2008 23:46 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: Re: xpath query > > Hi there, > I am still struggling with mostof this stuff, but I have a > question related to the original data. > > <ROOT> > <LEVEL2> > <B> > <a>100</a> > <b apply="1">100</b> > <c>100</c> > </B> > <C> > <a>100</a> > <b>100</b> > <c apply="1">100</c> > </C> > </LEVEL2> > </ROOT> > > If I create the following stylesheet I get 100 100 output > > <xsl:stylesheet > xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0"> > <xsl:template match="ROOT"> > <html> > <xsl:value-of select="LEVEL2/*/*[@apply='1']"/> > </html> > </xsl:template> > </xsl:stylesheet> > > What I am not clear on is why does this return values and not nodes? > Or is this really returning both nodes and I am getting the > value of each one because of the <xsl:value-of select="..."/> > expression? > > As far as I can figure the expression ROOT/LEVEL2/*/*[@apply='1']" > says give me the nodes that have the arrtibute apply=1 and > are grandchildren of level2. > > I kind of though to get both values I would have to do something like > > <xsl:template match="ROOT"> > <xsl:for-each select="LEVEL2/*/*[@apply='1']"> > <xsl:value-of select="."/> > </xsl:for-each> > </xsl:template> > > Sorry if this seems really trivial but it helps me to better > understand. > > -- > Thanks > Sean 
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