[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Return value from a template...
Batis DAVE wrote:
I want to return a variable value from a template based on this example: http://biglist.com/lists/xsl-list/archives/200205/msg01614.html but it's not working... Here's my code: <?xml version="1.0"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:output indent="yes" method="html" omit-xml-declaration="no" encoding="ISO-8859-1" /> <xsl:param name="delimiter" select="','"/> An xsl:call-template does not allow a select attribute. If you define parameters on your template with xsl:param then you can pass parameters to the called template using xsl:with-param. </xsl:variable> <xsl:value-of select="$idList"/> </xsl:template> The variable var is defined inside of the for-each but it is that way not available outside of it. </xsl:template> See comments above. I am not sure what you want to achieve, if you want your named template to concatenate the ids values then you might want to do it as follows: <xsl:template name="getIdList"> <xsl:param name="items"/> <xsl:for-each select="$items/ids"> <xsl:value-of select="."/> <xsl:if test="position() != last()"> <xsl:value-of select="$delimiter"/> </xsl:if> </xsl:for-each> </xsl:template> <xsl:template match="/root"> <xsl:call-template name="getIdList"> <xsl:with-param name="items" select="bib"/> </xsl:call-template> </xsl:template> The above is more or less guessing on how your XML input might look and what you want to achieve with your named template. If it does not help then you might want to post your XML input and tell us what you want to achieve. -- Martin Honnen http://JavaScript.FAQTs.com/
|
PURCHASE STYLUS STUDIO ONLINE TODAY!Purchasing Stylus Studio from our online shop is Easy, Secure and Value Priced! Download The World's Best XML IDE!Accelerate XML development with our award-winning XML IDE - Download a free trial today! Subscribe in XML format
|