[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Passing a list of arguments
On 11/9/07, Mathieu Malaterre <mathieu.malaterre@xxxxxxxxx> wrote: > test.xml: > <?xml version="1.0" encoding="UTF-8"?> > <article> > </article> > > test.xsl: > <?xml version="1.0" encoding="UTF-8"?> > <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0"> > <xsl:output method="xml" indent="yes" encoding="UTF-8"/> > <xsl:variable name="sections-list"> > <section> > <section>C.8.7.1.1.2</section> > <section>C.8.14.1.1</section> > <!-- ... --> > </section> > </xsl:variable> > <xsl:template match="article"> > <xsl:param name="extract-section"/> > <xsl:message> > <xsl:value-of select="$extract-section"/> > </xsl:message> > </xsl:template> > <xsl:template match="/"> > <xsl:for-each select="$sections-list"> > <xsl:apply-templates select="article"> > <xsl:with-param name="extract-section" select="$section"/> > </xsl:apply-templates> > </xsl:for-each> > </xsl:template> > </xsl:stylesheet> You seem to be missing something. I think, the root template should be: <xsl:template match="/"> <xsl:for-each select="$sections-list/section/section"> <xsl:apply-templates select="article"> <xsl:with-param name="extract-section" select="."/> </xsl:apply-templates> </xsl:for-each> </xsl:template> It's not clear to me what exactly is your requirement. But you seem to be writing a wrong XPath expression. -- Regards, Mukul Gandhi
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