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Re: Sorting a XML file with XSL
Subject: Re: Sorting a XML file with XSL
From: Buddhi Dananjaya <buddhi@xxxxxxxxxxxxxxxxxxx>
Date: Wed, 24 Oct 2007 15:01:38 +0530
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I tried with the XSL posted. But after transformation I am again getting
same XML as out put (not sorted)
Why it is mentioned as comment blocks are not uniques, as I feel they
are unique.. Main.cs, Text.cs, etc.
Florent Georges wrote:
Buddhi Dananjaya wrote:
Hi
Following is my sample XML file, I want to sort this base on
<comment> tag and make a new XML file using a style sheet
You can use the Modified Identity pattern:
<xsl:output indent="yes"/>
<!-- Identity transform -->
<xsl:template match="node()">
<xsl:copy>
<xsl:copy-of select="@*"/>
<xsl:apply-templates select="node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="root">
<xsl:copy>
<xsl:copy-of select="@*"/>
<xsl:apply-templates select="*">
<xsl:sort select="data/comment"/>
</xsl:apply-templates>
</xsl:copy>
</xsl:template>
The data/comment contents are not unique. If you want to order a
second field to perform more precise sorting, you can do so using a
second xsl:sort instruction. For instance, if you want to sort on
comment then on @name:
<xsl:apply-templates select="*">
<xsl:sort select="data/comment"/>
<xsl:sort select="data/@name"/>
</xsl:apply-templates>
Regards,
--drkm
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