RE: Search text and write the code

The output you are asking for is not legal XML (see below), so I am not clear on what to advise.

XML requires that all elements be properly nested. The output you have specified:

<item>
  <b>
    <label>1.1</label> 
      <para>Grundbegriffe
  </b>
  <xref pointer="p0002">2</xref>
      </para>
</item>

has the <b> element overlapping the <para> element.


In XML, you can't have "<b><para></b></para>", and that's what you've specified as your desired output.

-- 
Charles Knell
cknell@xxxxxxxxxx - email



-----Original Message-----
From:     Byomokesh Sahoo <sahoo.byomokesh@xxxxxxxxx>
Sent:     Wed, 5 Sep 2007 14:46:17 +0530
To:       xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject:   Search text and write the code

Hi All,

I have some problem in my project. I need text or number search in
text and write the code. Is it possible through XSLT?

My XML
===== 
<o1item><emphasis style="b">1.1 Grundbegriffe</emphasis> <hotlink
xref="p0002" xidtype="page">2</hotlink></o1item>

XSL File
======= 
<xsl:template match="o1item">
<xsl:text>
</xsl:text><item>
<xsl:call-template name="labelstring">
                   <xsl:with-param name="Text" select="."/>
    </xsl:call-template>

			<para><xsl:apply-templates /></para>
</item>
	</xsl:template>

<xsl:template name="labelstring">
             <xsl:param name="Text"/>
            <xsl:choose>
                    <xsl:when test="contains($Text, ' ')">
                           <label>
                          <xsl:value-of select="substring-before($Text, ' ')" />

                            </label>

                    </xsl:when>
            </xsl:choose>
        </xsl:template>

On the base my style sheet output is

<item><label>1.1</label><para><b>1.1 Grundbegriffe</b><xref
pointer="p0002">2</xref></para></item>

But I need output is..........

<item><b><label>1.1</label> <para>Grundbegriffe</b><xref
pointer="p0002">2</xref></para></item>

Please anyone suggest me what can i do.

Thanks
Byomokesh Sahoo



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