RE: grouping-problem

Use group-by="(@associationName, '')[1]"

so that elements with no @associationName get a grouping key of "".

Michael Kay
http://www.saxonica.com/ 

> -----Original Message-----
> From: Annina.Hirschi-Wyss@xxxxxxxxxxxx 
> [mailto:Annina.Hirschi-Wyss@xxxxxxxxxxxx] 
> Sent: 14 June 2007 09:59
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject:  grouping-problem
> 
> Hi,
> I'm working with
> XSLT 2
> Saxon 8
> And I am a newbie with XSLT...
> 
> ----
> Here is the XML file
> "stats.xml"
> 
> <statistic>
> <class name="CI_Citation" associationName="citation" 
> count="50"> </class> <class name="CI_Citation" 
> associationName="title" count="100"> </class> <class 
> name="MD_Metadata" count="300"> </class> <class 
> name="MD_Metadata" associationName="parentId" count="3"> 
> </class> <class name="CI_Citation" associationName="citation" 
> count="60"> </class> <class name="CI_Citation" 
> associationName="title" count="200"> </class> <class 
> name="MD_Metadata" count="50"> </class> <class 
> name="MD_Metadata" associationName="parentId" count="10"> 
> </class> [...] </statistic>
> ----
> 
> Output should be a csv-textfile like:
> 
> CI_Citation		citation	110
> 			title		300
> MD_Metadata				350
> 			parentId	13
> ----
> 
> I managed quite well, but only did my XSLT not consider the 
> class MD_Metadata without the "associationName":
> 
> "stats.xsl"
> 
> <?xml version="1.0" encoding="ISO-8859-1"?> <xsl:stylesheet 
> version="2.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
> 	<xsl:output encoding="ISO-8859-1"/>
> 	<xsl:output method="text"/>
> <xsl:template match="/">
> 		<xsl:apply-templates select="statistic"/> 
> </xsl:template> [...]
> <xsl:for-each-group select="class" group-by="@name">	
>   <xsl:value-of select="current-grouping-key()"/>
> 		<xsl:for-each-group select="current-group()"
> group-by="@associationName" >
> 			<xsl:text>;</xsl:text>
> 			<xsl:value-of select="current-grouping-key()"/>
> 			<xsl:text>;</xsl:text>
> 			<xsl:value-of 
> select="sum(current-group()/@count)"/>
>             </xsl:for-each-group>
> </xsl:for-each-group>
> [...]
> ----
> 
> Is there a possibility to list the class MD_Metadata even if 
> there is no "associationName"? Thanks for your reply!