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Re: Friday challenge: XSLT thats creates XPaths for m
Subject: Re: Friday challenge: XSLT thats creates XPaths for meaningfully equivalent comparisons of XML files
From: "Andrew Welch" <andrew.j.welch@xxxxxxxxx>
Date: Fri, 13 Apr 2007 16:00:50 +0100
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On 4/13/07, Dimitre Novatchev <dnovatchev@xxxxxxxxx> wrote:
Some quick thoughts:
> <checkXML>
> <xml src="file:/C:/test.xml">
> <check>/root[1]/foo[1]/text[1] = 'foo'</check>
> <check>/root[1]/foo[1]/@fooatt = 'att'</check>
> <check>/root[1]/bar[1]/text[1] = 'bar'</check>
> <check>/root[1]/bar[2]/text[1] = 'baz'</check>
> </xml>
> </checkXML>
1. Checking if the above XPath expressions all evaluate to true() is
not a guarantee that the two documents are the same. One of them could
be a prefix (has all of the first N nodes in document order of the
other document, but the other document has still more nodes after the
"first N nodes"). Therefore, an essential XPath expression that is
missing is:
count(//node() | //@* | //namespace::*) = N
This XPath expression illustrates also that according to our
definition of "document equality" some of its subexpressions and the
right-hand-side of the equality test above may differ when "equality"
is defined in a different way -- for example, do all attribute and
namespace nodes matter, do we take into account comment nodes and/or
processing instructions, ..., etc.
There are even such people, according to whom the following are different:
<someElement/>
and
<someElement></someElement>
and a lot of similar purely lexical differences (escaped text or
CDATA, double or single quotes, explicit declaration of a namespace
node inherited from the parent, order of attributes, ..., etc.)
Hi Dimitre,
The point of my exercise is not to guarantee that xml documents are
canonically identically, but that they are meaningfully equivalent.
I'm not talking about lexical similarity, but infoset similarity,
think HTML output.
This is just an idea, so I'm open to suggestions.
Given the task of upgrading a set of XSLT 1.0 transforms to XSLT 2.0,
how do you ensure the output remains consistent after the upgrade?
How can you be sure that the "improvements" you've made haven't broken
any existing transforms? A canonical set of comparisons would flood
you with insignificant results, so you're more concerned with
"meaningful equivalent" results. Perhaps I have the wrong approach
here...
I do use XSDs and Selenium tests, but I think there's room for another
tool that allows XSD, XPaths and XSLTs to check the correctness of the
XML.
2. What is even more important, even if all issues described in 1.
above have been solved/agreed-upon, the fact that the result of an
XSLT 2.0 transformation is the same as the result of an XSLT 1.0
transformation of a given document *does not guarantee* that the two
transformations will have the same result when applied on another xml
document.
To put it in other words, the proposed tool will be effective in
showing that two transformations do not produce the same results, but
it cannot be used in ascertaining that two transformations will always
produce the same result.
I agree, but I'm talking about infoset equivalence rather than lexical
equivalence.
cheers
andrew
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Andrew Welch - 13 Apr 2007 15:01:17 -0000 <=
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