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Re: Friday challenge: XSLT thats creates XPaths for m

Subject: Re: Friday challenge: XSLT thats creates XPaths for meaningfully equivalent comparisons of XML files
From: "Robert Koberg" <rob@xxxxxxxxxx>
Date: Fri, 13 Apr 2007 06:58:18 -0400
Re:  Friday challenge: XSLT thats creates XPaths for  m
On Fri, 13 Apr 2007 06:48:26 -0400, Andrew Welch
<andrew.j.welch@xxxxxxxxx> wrote:

<xsl:for-each select="//*">

Maybe this should be select="node()" and then apply-templates on it and match all possible nodes??

best,
-Rob


				<xsl:variable name="path" select="concat('/', string-join(for $x
in ancestor-or-self::*
				return concat($x/local-name(), '[',
count(.|$x/preceding-sibling::*[name() = current()/name()]), ']'),
'/'))" as="xs:string"/>
				<xsl:for-each select="text()[normalize-space(.) != '']">
					<check><xsl:value-of select="concat($path, '/text[', position(),
'] = ''', .,'''')"/></check>
				</xsl:for-each>
				<xsl:for-each select="@*">
					<check><xsl:value-of select="concat($path, '/@', name(), ' = ''',
., '''')"/></check>
				</xsl:for-each>
			</xsl:for-each>
		</xml>
	</checkXML>
</xsl:template>

The result is:

<checkXML>
   <xml src="file:/C:/test.xml">
      <check>/root[1]/foo[1]/text[1] = 'foo'</check>
      <check>/root[1]/foo[1]/@fooatt = 'att'</check>
      <check>/root[1]/bar[1]/text[1] = 'bar'</check>
      <check>/root[1]/bar[2]/text[1] = 'baz'</check>
   </xml>
</checkXML>

The above transform is quick attempt to demonstrate the problem, I'm
sure it can be improved on.

Also, if there are any thoughts about this approach it would be good
to hear them.

cheers
andrew

ps. CheckXML is a work in progress, contact me if you'd like to be
involved.



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