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Res: org.apache.xpath.objects.XRTreeFrag error

Subject: Res: org.apache.xpath.objects.XRTreeFrag error
From: Lepoldo Melo <leopoldosmj@xxxxxxxxxxxx>
Date: Sun, 25 Mar 2007 19:29:14 -0700 (PDT)
Res:  org.apache.xpath.objects.XRTreeFrag error
I've already done the changes, but I'm still getting the error on line
"<xsl:for-each select="$node/*/*">". I don't know how to avod this tree
fragment.

The new code is bellow.

    <xsl:template name="check_identical">
<xsl:param name="comp1"/>
        <xsl:param name="comp2"/>
<xsl:variable name="string1">
            <xsl:call-template name="stringify">
<xsl:with-param name="node" select="$comp1"/>
            </xsl:call-template>
</xsl:variable>
        <xsl:variable name="string2">
<xsl:call-template name="stringify">
                <xsl:with-param
name="node" select="$comp2"/>
            </xsl:call-template>
</xsl:variable>
        <xsl:value-of select="$string1=$string2"/>
</xsl:template>

    <xsl:template name="stringify">
        <xsl:param
name="node"/>
        <xsl:for-each select="$node/*/*">
<xsl:choose>
                <xsl:when test="boolean(local-name())">&lt;
<xsl:value-of select="local-name()"/>
                    <xsl:variable
name="pos" select="position()"/>
                    <xsl:for-each
select="@*">
                        <xsl:text> </xsl:text>
<xsl:value-of select="local-name()"/>="<xsl:value-of
select="."/>"</xsl:for-each>
                    <xsl:call-template
name="stringify">
                        <xsl:with-param name="node"
select="."/>
                    </xsl:call-template>&lt;/
<xsl:value-of select="local-name()"/>&gt;</xsl:when>
<xsl:otherwise>
                    <xsl:value-of
select="normalize-space(.)"/>
                </xsl:otherwise>
</xsl:choose>
        </xsl:for-each>
    </xsl:template>


Thanks a lot.
Leopoldo


----- Mensagem original ----
De: Michael Kay <mike@xxxxxxxxxxxx>
Para: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Enviadas: Domingo, 25 de Margo de 2007
20:42:07
Assunto: RE:  org.apache.xpath.objects.XRTreeFrag error

If you
make the changes to avoid the unnecessary copying of data into result
tree
fragments (as suggested in my earlier response) then you should not be
getting
this error.

Michael Kay
http://www.saxonica.com/

> -----Original
Message-----
> From: Lepoldo Melo [mailto:leopoldosmj@xxxxxxxxxxxx] 
> Sent:
26 March 2007 00:26
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: Res:
 org.apache.xpath.objects.XRTreeFrag error
> 
> My code is ok, but it
doesn't work with Xalan 2.5.2.
> 
> The error is described at 
>
http://www.biglist.com/lists/xsl-list/archives/200505/msg00391.html. 
> 
> The
XRTreeFrag error happens on line "<xsl:for-each 
> select="$node/*/*">".
> 
>
----- Mensagem original ----
> De: Florent Georges <darkman_spam@xxxxxxxx>
>
Para: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Enviadas: Domingo, 25 de Margo de 2007
14:29:34
> Assunto: Re:  org.apache.xpath.objects.XRTreeFrag error
> 
>
Lepoldo Melo wrote:
> 
>   Hi
> 
> > Okay. Thanks, but I still don't know how
to solve the line 
> > "<xsl:for-each select="$node/*/*">".
> 
>   What do you
mean by "solving"?
> 
>   Your code seems ok with that, both in XSLT 1.0 and
2.0 (as 
> long as in XSLT 1.0 you pass a reference to an input tree, 
> and
what you showed is not enough to be sure on that point).
> 
>   So what
exactly is the problem?
> 
>   Regards,
> 
> --drkm
> 
> 
> 
> 
> 
> 
> 
> 
>
> 
> 
> 
> 
> 
> 
> 
> 
> 
> 
> 
> 
> 
>     
> 
>     
>         
>
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