Re: &amp;

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Subject: Re: &amp;
From: Marco <spinmar@xxxxxxxxx>
Date: Wed, 21 Mar 2007 12:53:17 +0100

David Carlisle ha scritto:

I have a xml document with:

......
<NODE n="1" url="url1" visible_url="url2?escape&amp;chars"></NODE> ..
this is almost certainly a mistake in the input and if you have control over the generation of these files, you should fix the generator to produce <NODE n="1" url="url1" visible_url="url2?escape&chars"></NODE>

The problem is that I don't produce the xml but I receive it from an external source.

and it's ok; the problem is the onmouseover attribute where I get:
disable-output-escaping is defined to do nothing in attribute values.
It's almost always a bad idea to use d-o-e in any case.
you need to replace & by &, in XSLT2, you could use

select="replace(@visible_url,'&amp;',' &')"

in XSLT1 you could use one of the many replace templates posted to this list, or the faq to do the same transformation.

For example I can use this one:

<xsl:template name="replaceUrl"> <xsl:param name="url" /> <xsl:choose> <xsl:when test="contains($url, '&amp;')"> <xsl:value-of select="concat(substring-before($url, '&amp;'), '&')" disable-output-escaping="yes" /> <xsl:call-template name="replacee"> <xsl:with-param name="url"><xsl:value-of select="substring-after($url, '&amp;')" disable-output-escaping="yes"/></xsl:with-param> </xsl:call-template> </xsl:when> <xsl:otherwise> <xsl:value-of select="$url" disable-output-escaping="yes" /> </xsl:otherwise> </xsl:choose> </xsl:template>

For Abel:

my javascript function (ss) on onmouseover shows the url in the status bar of browser and I have to use it. So I'd like to find a method to solve my problem in XSL 1.0.

Best regards

David

Current Thread
&amp; Marco - 21 Mar 2007 11:20:37 -0000 David Carlisle - 21 Mar 2007 11:28:15 -0000 Marco - 21 Mar 2007 11:58:41 -0000 <= David Carlisle - 21 Mar 2007 12:05:34 -0000 Abel Braaksma - 21 Mar 2007 11:35:22 -0000

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