[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: Transforming a non-hierarchical XML into a hierar
I'm guessing from your choice of element names that your hierarchic structure is positional rather than defined by pointers. This makes it a positional grouping problem. Such problems are always much easier in XSLT 2.0, so you need to make it clear whether you want a 1.0 or a 2.0 solution. Michael Kay http://www.saxonica.com/ > -----Original Message----- > From: SEXpeare [mailto:sexpeare@xxxxxxxxx] > Sent: 08 March 2007 10:20 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: Transforming a non-hierarchical XML into a > hierarchical one > > Hello everybody, I have to transform a non hierarchical XML: > > <sumario> > <seccion txt=""/> > <subseccion txt=""/> > <organismo txt=""/> > <anuncio txt=""/> > <organismo txt=""/> > <anuncio txt=""/> > <organismo txt=""/> > <anuncio txt=""/> > <subseccion txt=""/> > <organismo txt=""/> > <anuncio txt=""/> > <seccion txt=""/> > <subseccion txt=""/> > <organismo txt=""/> > <anuncio txt=""/> > ... > </sumario> > > into a hierarchical XML, doing this via XSLT. The result must > be like this: > > <sumario> > <seccion id=""> > <subseccion id=""> > <organismo id=""> > <anuncio> > </anuncio> > ... > > </organismo> > </subseccion> > </seccion> > ... > </sumario> > > I would apreciate any idea or advice, thx.
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