[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Transforming tabular information to hierarchical
On 2/13/07, Simon Shutter <simon@xxxxxxxxxxx> wrote:
If I have a tabular data set that defines parent-child relationships, is it possible to transform this into a hierarchical tree format using XSLT?
<xsl:output indent="yes" encoding="US-ASCII"/> <xsl:param name="pathToCSV" select="'file:///c:/temp/test.csv'"/> <xsl:template name="main"> <xsl:choose> <xsl:when test="unparsed-text-available($pathToCSV)"> <xsl:variable name="csv" select="unparsed-text($pathToCSV)"/> <xsl:variable name="lines" select="tokenize($csv, '
')" as="xs:string+"/> <xsl:variable name="elemNames" select="tokenize($lines[1], ',')" as="xs:string+"/> <root> <xsl:for-each select="$lines[position() > 1]"> <row> <xsl:variable name="lineItems" select="tokenize(normalize-space(.), ',')" as="xs:string+"/> <xsl:for-each select="$elemNames"> <xsl:variable name="pos" select="position()"/> <xsl:element name="{normalize-space(.)}"> <xsl:value-of select="$lineItems[$pos]"/> </xsl:element> </xsl:for-each> </row> </xsl:for-each> </root> </xsl:when> <xsl:otherwise> <xsl:text>Cannot locate : </xsl:text><xsl:value-of select="$pathToCSV"/> </xsl:otherwise> </xsl:choose> </xsl:template> </xsl:stylesheet>
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