RE: Identify transform with disabled output escaping

There are two common forms of identity transform. The one with

<xsl:template match="node()|@*">

relies on xsl:copy to copy the text nodes

The one with <xsl:template match="*"> relies on the built-in template rule
for text nodes to copy the text nodes.

But in either case, you can write a template rule for text nodes:

<xsl:template match="text()" priority="10">
  <xsl:value-of select="." disable-output-escaping="yes"/>
</xsl:template>

that will override the default.

Though why on earth you would want to disable output escaping on all the
text in your document defeats me.

Michael Kay
http://www.saxonica.com/


> -----Original Message-----
> From: Peter Szinek [mailto:peter@xxxxxxxxxxxxxxxx] 
> Sent: 15 November 2006 18:04
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject:  Identify transform with disabled output escaping
> 
> Hello all,
> 
> I have been browsing the archives for at last 2 hours and 
> could not find the answer - though it seems so trivial.
> 
> I have found some older messages claiming that the identify 
> transformation can not be done without xsl:copy. However, 
> disable-output-escaping is valid for xsl:value and xsl:text 
> only (i.e. not for xsl:copy). For me, these two statements 
> imply that the identify transformation can not be done with 
> output escaping disabled.
> 
> Is there a workaround for this?
> 
> Thanks,
> Peter