Re: Grouping the elements

<xsl:template match="Root">
   <xsl:copy>
       <xsl:apply-templates
           select="year[position() = last()]" />
       <xsl:apply-templates
           select="month[position() = last()]" />
       <xsl:apply-templates
           select="week[position() = last()]" />
       <xsl:apply-templates
           select="day[position() = last()]" />
   </xsl:copy>
</xsl:template>

<xsl:template match="*">
   <xsl:variable name="curName" select="name()" />
   <xsl:if test="count(../*[name() = $curName]) > 1">
       <xsl:element name="{local-name(.)}List">
           <xsl:copy-of select="../*[name() = $curName]" />
       </xsl:element>
   </xsl:if>
   <xsl:if test="count(../*[name() = $curName]) = 1">
       <xsl:copy-of select="." />
   </xsl:if>
</xsl:template>

Best regards,
Abel Braaksma
http://abelleba.metacarpus.com

Hi,

I have the following xml for my input..

<?xml version="1.0" encoding="UTF-8"?>
<Root>
    <year>2006</year>
    <year>2007</year>
    <year>2008</year>
    <week>1</week>
    <day>01</day>
    <day>02</day>
</Root>

My expected output is

<Root>
    <yearList>
        <year>2006</year>
         <year>2007</year>
        <year>2008</year>
     <yearList>
    <week>1</week>
    <dayList>
         <day>01</day>
         <day>02</day>
     </dayList>
</Root>

I want to group the element using xslt 1.0 and here element name is not fixed..it will be varied. when we have the same element then we need a parent element which have the element's name with List (i.e., yearList)

Is it possible to grouping in xslt1.0?

regards,
raj