Re: String Replacement in XML using XSLT

Or I could make all replacements using a single template only:

<content name="subject"> Hello <insert>BUYERS_NAME</insert></content>

<xsl:template match="insert">
 <xsl:value-of select="/*/*[name() = current()]">
</xsl:template>

<xsl:variable name="content-tree">
   <xsl:for-each select="//content">
      <xsl:copy>
       <xsl:for-each select="tokenize(., '\[|\]')">
           <xsl:if test="position() mod 2">
               <text><xsl:value-of select="." /></text>
           </xsl:if>
           <xsl:if test="not(position() mod 2)">
               <insert><xsl:value-of select="." /></insert>
           </xsl:if>
       </xsl:for-each>
     </xsl:copy>
   </xsl:for-each>
</xsl:variable>

<content name="subject">
   <text>Hello </text>
   <insert>BUYERS_NAME</insert>
</content>
<content name="text">
   <text>REF Order </text>
   <insert>ORDER_NUMBER</insert>
</content>

Cheers,
Abel Braaksma
http://abelleba.metacarpus.com