Re: Numbering 1st 2nd 3rd ...

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Subject: Re: Numbering 1st 2nd 3rd ...
From: Abel Braaksma <abel.online@xxxxxxxxx>
Date: Wed, 13 Sep 2006 00:22:14 +0200

Hi Spencer,

So you are stuck with XSTL 1.0? Let me give it a try. Someone already pointed out that 11..13 are exceptions to the mod 10 rule. This is the simplest I could think of and it works up to 1000 at least (didn't check every number though) and it may even work for higher numbers. Lucky thing: not a huge <xsl:choose>, just a tiny one.

Mark the line that says:
<xsl:with-param name="top" select="200" />

Set it to any value to extend the list. Every number from 1 to $top is output. You prob. only need the tiny piece that is called "ordinal". The stylesheet works with any input, as it does not do anything with the input.

Have fun with it ;)

<?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/> <xsl:template match="/" > <ordinals> <xsl:call-template name="sequence"> <xsl:with-param name="top" select="200" /> </xsl:call-template> </ordinals> </xsl:template>  <xsl:template name="sequence" > <xsl:param name="top" /> <xsl:if test="$top > 1" > <xsl:call-template name="sequence"> <xsl:with-param name="top" select="$top - 1" /> </xsl:call-template> </xsl:if> <ord> <xsl:value-of select="$top" /> <xsl:call-template name="ordinal"> <xsl:with-param name="number" select="$top" /> </xsl:call-template> </ord> </xsl:template>  <xsl:template name="ordinal"> <xsl:param name="number" /> <xsl:choose> <xsl:when test="$number mod 100 = 11">th</xsl:when> <xsl:when test="$number mod 100 = 12">th</xsl:when> <xsl:when test="$number mod 100 = 13">th</xsl:when> <xsl:when test="$number mod 10 = 3">rd</xsl:when> <xsl:when test="$number mod 10 = 2">nd</xsl:when> <xsl:when test="$number mod 10 = 1">st</xsl:when> <xsl:otherwise>th</xsl:otherwise> </xsl:choose> </xsl:template> </xsl:stylesheet>

Cheers,
Abel Braaksma
http://abelleba.metacarpus.com

Steve wrote:

Recursive algorithm? (template which starts at the first, and calls
itself passing param = param + 1).

-s

On 9/12/06, Spencer Tickner <spencertickner@xxxxxxxxx> wrote:

Hi List,

Thanks in advance for the help. I'm wondering if there's an elegant
way to format position() like:
1st 2nd 3rd and so on. I've looked through google for a format that
works with xsl:number, but haven't been able to find anything. I know
I could always do a long <xsl:choose> statement, but it feels wrong.
Anyway here's some samples

XML

<root>
 <num>foo</num>
 <num>bar</num>
</root>

Output

<root>
<num>1st</num>
<num>2nd</num>
</root>

Cheers,

Spencer

Current Thread
Re: Numbering 1st 2nd 3rd ..., (continued) Spencer Tickner - 12 Sep 2006 20:45:34 -0000 Michael Kay - 12 Sep 2006 21:53:55 -0000 Abel Braaksma - 12 Sep 2006 21:49:22 -0000 Steve - 12 Sep 2006 21:54:34 -0000 Abel Braaksma - 12 Sep 2006 22:22:28 -0000 <= Spencer Tickner - 12 Sep 2006 22:31:22 -0000 pnorton - 12 Sep 2006 21:50:55 -0000

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