[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: values in sequence after tokenize
The regex given to tokenize determines the separator between tokens, not the content of the tokens. I'm not quite sure what result you expect here (or in general). You can probably tackle it using xsl:analyze-string, which is more powerful than tokenize(). Michael Kay http://www.saxonica.com/ > -----Original Message----- > From: andrew welch [mailto:andrew.j.welch@xxxxxxxxx] > Sent: 11 July 2006 14:56 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: values in sequence after tokenize > > Given a string of characters: > > <xsl:variable name="string" select="'aa^a^aaa^aaaaaa^aa^aa^aaaaaa^'"/> > > I want to break that string into substrings up to a given > length, so that the words including circumflexes ('^') are no > longer than the specified length. > > I'm trying do this with a regex (in this example the length is 6): > > <xsl:variable name="substring" select="tokenize($string, '.{1,6}\^')" > as="xs:string*"/> > > This regex must be wrong because $substring now holds a > sequence of 6 items (as expected), but each of those items > appears to be ' '. For example this bit of debug: > > x<xsl:value-of select="for $y in $substring return concat($y, 'z')"/>x > > produces: > > xz z z z z zx > > What's the correct regex for this problem? > > thanks > andrew
|
PURCHASE STYLUS STUDIO ONLINE TODAY!Purchasing Stylus Studio from our online shop is Easy, Secure and Value Priced! Download The World's Best XML IDE!Accelerate XML development with our award-winning XML IDE - Download a free trial today! Subscribe in XML format
|