[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] [no subject]<xsl:template match="xref"> <xsl:apply-templates select="@xrefid"/> </xsl:template> Do you have a template to handle that attribute or are you letting your XSLT processor take its default behavior (which is to put the text value of the attribute into the output)? If you are letting it take its default behavior, you'll never get the FO tags you need. Also, it's easier (and more maintainable) to just do it all here in this template rather than call another one from this point. To say more, I'd have to see more of your transform. Jay Bryant Bryant Communication Services ----- Original Message ----- From: "Tech Savvy" <tecsavvy@xxxxxxxxx> To: <jay@xxxxxxxxxxxx> Sent: Thursday, April 27, 2006 10:35 AM Subject: Re: Question about cross references Hello: I have still not been able to find a solution to this problem. Would you have any other suggestions to this. Thank you On 4/26/06, Jay Bryant <jay@xxxxxxxxxxxx> wrote: > That's very possible (and a common task for those of us, including me, who > use XSLT to mangle documents). > > To handle it, you need to write a template to handle xref nodes. Something > like this: > > <xsl:template match="xref"> > <fo:basic-link internal-destination="{@xrefid}"><xsl:value-of > select="."/></fo:basic-link> > </xsl:template> > > You also need to create matching ids (the actual destinations) within the > FO, so you need to do that wherever you have an id attribute in the source. > Something like this: > > <xsl:template match="list1"> > <fo:block> > <xsl:if test="@id"> > <xsl:copy-of select="@id"/> > </xsl:if> > <xsl:value-of select="."/> > </fo:block> > </xsl:template> > > Of course, you'll probably want to use the proper list elements for your > list. I just stuck it in a block for simplicity's sake. > > Just remember that you need both a link and a corresponding id for the link. > > Also, if you can have id attributes in other than list1 nodes (seems > likely), you'll want to either handle it in each template or write a > separate template just to handle id attributes. > > If you have more trouble, post back to the list. > > HTH > > Jay Bryant > Bryant Communication Services > > ----- Original Message ----- > From: "Tech Savvy" <tecsavvy@xxxxxxxxx> > To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx> > Sent: Wednesday, April 26, 2006 1:39 PM > Subject: Question about cross references > > > Hello: > > I am trying to achieve a corss ref in xslt and xsl:fo. > > Here is wht the XML looks like: > < > > list1 id="l1"> > <text> > > <para>Some text</para> > > </text> > > </list1> > > <list1 id="l2"> > > > <text> > > <para>Some other text as in list <xref xrefid ="l1"/>A.</para> > > </text> > > </list1> > > The desired result is: > > 1. Some text > 2. Some other text as in list 1A. > > But the current result is: > 1. Some text > 2. Some other text as in list l1A. > > > I want to get the reference from the xrefid and put it on the text. > The lists are formatted on the XSLT as eithr numbers(1,2) or (A,B) > etc. > > Is there nay way this can be achieved thru XSLT. > > Thanks in advance for your help.
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