1 + 1 = 11

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Subject: 1 + 1 = 11
From: Eric White <eric.white@xxxxxxxxxxx>
Date: Tue, 18 Apr 2006 12:18:47 -0500

What am I missing? I define a parameter, get the highest existing row number and I want to add a value to it -- so I can add the next table row with a new index. I get the index value correctly, but when I add one (1) to it, I get the string "11", rather than the number 2. Note that I specifically set the param to a number via the number() function. I've also tried using the number() function inside the select attribute of the apply-templates element, trying to coerce the result, but to no avail.

<xsl:template match="ntpServerTable"> <xsl:param name="rowindex"> <xsl:for-each select="ntpServerTableRow"> <xsl:sort select="ntpServerTableRowIndex" data-type="number" order="descending" /> <xsl:choose> <xsl:when test="position() = 1"> <xsl:value-of select="number(ntpServerTableRowIndex)"/> </xsl:when> <xsl:otherwise>0</xsl:otherwise> </xsl:choose> </xsl:for-each> </xsl:param> <xsl:apply-templates select="ntpServerTableRow"/> <ntpServerTableRowIndex><xsl:value-of select="$rowindex+1"/></ntpServerTableRowIndex>

Current Thread
1 + 1 = 11 Eric White - 18 Apr 2006 17:19:09 -0000 <= <Possible follow-ups> Gosselin, Michael - 18 Apr 2006 17:27:56 -0000 Wendell Piez - 18 Apr 2006 17:41:38 -0000

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Re: XSL-FO Table Problem / Ma, G. Ken Holman	Thread	RE: 1 + 1 = 11, Gosselin, Michael
RE: creating tags around a st, Michael Kay	Date	RE: 1 + 1 = 11, Gosselin, Michael
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