[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: formatting of lists
Hi Dieter, Please try this stylesheet <?xml version="1.0"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:output method="xml" indent="yes" /> <xsl:template match="/people"> <html> <head> <title/> </head> <body> <table> <tbody> <xsl:call-template name="generateTRs"> <xsl:with-param name="nodeset" select="person" /> </xsl:call-template> </tbody> </table> </body> </html> </xsl:template> <xsl:template name="generateTRs"> <xsl:param name="nodeset" /> <xsl:if test="$nodeset"> <tr> <td><xsl:value-of select="$nodeset[1]/@name" /></td> <td><xsl:value-of select="$nodeset[2]/@name" /></td> <td><xsl:value-of select="$nodeset[3]/@name" /></td> </tr> <xsl:call-template name="generateTRs"> <xsl:with-param name="nodeset" select="$nodeset[position() > 3]" /> </xsl:call-template> </xsl:if> </xsl:template> </xsl:stylesheet> Regards, Mukul On 9/6/05, Dieter Bvll <dieter.boell@xxxxxx> wrote: > > Dear community > > I have following problem. > > It is a list of elements given e.g. > > <people> > <person id="id1" name="John"/> > <person id="id2" name="Peter"/> > <person id="id3" name="Anne"/> > <person id="id4" name="Joan"/> > <person id="id5" name="Pit"/> > <person id="id6" name="Jeff"/> > <person id="id7" name="Chris"/> > <person id="id8" name="Elke"/> > <person id="id9" name="Mark"/> > <person id="id10" name="Frank"/> > <person id="id11" name="Tom"/> > <person id="id.." name=".."/> > </people> > > The aim is to generate a table in HTML with 3 or 4 columns but so many rows as necessary. > Like that: > <table> > <tbody> > <tr> > <td>John</td> > <td>Peter</td> > <td>Anne</td> > </tr> > <tr> > <td>Joan</td> > <td>Pit</td> > <td>Jeff</td> > </tr> > <tr> > <td>Chris</td> > <td>Elke</td> > <td>Mark</td> > </tr> > <tr> > <td>Frank</td> > <td>Tom</td> > </tr> > </tbody> > </table> > > Sorry but I have no idea how to do that with xslt :( > I am thankful for every help. > > Many thanks in advance > > Dieter
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