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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: RE: XML to HTML
 Is there any other shortest way to get the TopicGroup in H1 and all the src present in that in h2. Same for Topic in h1 and src presents in that in h2. I'm not totally sure what your goal is, because of the line noise. Give this stylesheet a try: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" exclude-result-prefixes="tm" xmlns:tm="urn:xmlintl-tm-tags"> <xsl:output method="xml" indent="yes"/> <xsl:template match="/">
<html>
<head>
<style type="text/css">
h1.group {background:#09C;color:black;font-size:xx-large}
</style>
</head>
<body>
<xsl:apply-templates/>
</body>
</html>
</xsl:template><xsl:template match="qxf"> <xsl:apply-templates select="docmain/Chapter/TopicGroup"/> </xsl:template> <xsl:template match="TopicGroup"> <h1 class="group"> <xsl:value-of select="Title//src"/> </h1> <xsl:apply-templates select="BodySummary//src"/> <xsl:apply-templates select="Topic"/> </xsl:template> <xsl:template match="Topic"> <h2 align="center"><xsl:value-of select="Title//src"/></h2> <xsl:apply-templates select="BodyConcept//src"/> </xsl:template> <xsl:template match="src"> <p><xsl:apply-templates/></p> </xsl:template> <xsl:template match="src[ancestor::Note]"> <h3>Note: <xsl:apply-templates/></h3> </xsl:template> </xsl:stylesheet>
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