RE: Using a template to transform a node attribute

Question: 
To use attribute element, don't you need a TAG?

Example:
<xsl:template match="/report/version[@id]">
	<tag>
		<xsl:attribute name="id">bar</xsl:attribute>
	</tag>
</xsl:template>



-----Original Message-----
From: Emerson, Matt [mailto:Matt.Emerson@xxxxxxx] 
Sent: Monday, September 12, 2005 10:19 AM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject:  Using a template to transform a node attribute

Hello,

This is probably an easy question, but I haven't been able to find an
answer.

I have a node like this...
<report>
	<version id="foo">
		<data>1234</data>
	</version>
</report>

I wanted to write a template that would change the "id" attribute based
on some other information in the document so I wrote...

<xsl:template match="/report/version[@id]">
	<xsl:attribute name="id">bar</xsl:attribute>
</xsl:template>

But the parser tells me that I have a syntax error when trying to
specify the attribute "id" properly.  Any ideas?

I am using a simple identity transform to process the rest of the node.

Thanks,

Matt