RE: [xpath] all following sibling nodes upto first oc

In general in XPath if you want to find all nodes on an axis up to the first
one that satisfies condition X, the approach is:

following-sibling::node() except
following-sibling::node()[X][1]/following-sibling::node()

The except operator is in XPath 2.0 but not in XPath 1.0. In XPath 1.0, to
write "A except B", you code it as

A[count(.|B)!=count(B)]

You can expect the performance of the resulting expression to be fairly
awful; a recursive solution at the XSLT level that steps along the axis
until it finds a node satisfying X is likely to be much more efficient.

Michael Kay
http://www.saxonica.com/

> -----Original Message-----
> From: geoff hopkins [mailto:geoffhopkins123@xxxxxxxxx] 
> Sent: 11 August 2005 13:34
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject:  [xpath] all following sibling nodes upto first 
> occurace of specific text value
> 
>  I understand this is a xslt forum but there does not
>  seem to be any decent xpath places...
>  
>  I need a xpath expression to be used with a for-each
>  loop... context node is X.Parent select the next
>  items
>  until it finds the next occurance of X.Parent or
>  END-OF-DATA as the text value of the node
>  
>  e.g. the following xml is a typical xml file
>  
>  <?xml version="1.0" encoding="utf-8"?>
>  <root>
>  	<node>X.Parent</node>
>  	<node>Y.Child</node>
>  	<node>Y.Child</node>
>  	<node>X.Parent</node>
>  	<node>Y.Child</node>
>  	<node>END-OF-DATA</node>
>  </root>
>  
>  Thanks...
>  
>  Geoff
> 
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